## June 17, 2009

june 17,2009 oling green kENTUCKY usa
[email protected] = john kirk gray
310 j. bragg rd., edmonton,ky 42129 USA.
For mathemastical expression of three variables to describe any natural isotope and many lab- made nuclear FUSION products
!. let A1 +B1 + C1 = at no. "A"
for all chemical species 1 to 118,this year,sofar...
2/ Let 3A + 2B + 1C = Atomic mass integer
"Z" within limit: 1 At no "A" is lees than or equal to Z which is lees thanor equal to 3 atomic numbers" 3A" (most nuclides and isotopes lie between two and three Atomic numbers in the Atomic mass integer
e.g. For 79 Au 197, 197 lies between 2 x 79(158) and 3 x 79 (237)
in association with the two equations bove
combined: A (1,3) + B(1,2 ) + C(1,1) = (79,197) = {A,Z)

To solve for AB And C:
Set C = 0
from Z at 197 subtract 2 A or 158
197 - 158 = 39 This is A of (tritium(1H3))
For B of Deuterium
From At no 79 subtrat A (t) just obtained
79-39 = 40 -= B(deuterium)
Plug into formula
239 Tritium + 40 deuterium + 0 Protium = 79,197 = energy k

A confirmation of the validity of the expression may be easier with Mercury...
40 tritium = 40 deuterium + 0 protium = 80(Mercury: Hg) 200 Inthat it is liquid at room temperature,shiny,silvery color and subject to gravity pull...If not lost somewhere inthe home built reactor chamber,shoul be very easy to spot visually...confirming the efficacious thesis,
AND with one less deuterium
39 tritium + 39 deuterium + 0 protium = 78Platinum 195, transmutation of hydrogen nuclides may prove less es xpensive if there is some Platinum to SELL on EBAy or at the money getting places...
for silver 47 108
set c= 0,find a then find B and plug in formula..

108 - (2x47=94) =14 Tritium
from 47 subtract 14 for B deutreium
47 -14 = 33 = B deuterium?
14 Tritium + 33 Deuterium + 0 protium = 47,Silver 108 (orBUST!!) = energy constant K.

I got NO Kilowatthours saved up at my bank or in the checking account there. no elwctron volts in the SAVINGS AND LOAN either... My credit sucks...

from 108 subtract 2 x 47 = 94

MAY 27,2010 BOWLING GREEN KENTUCKY

For a nuclesr fusion FOrmuls:

A(tritium) * B(Deuterium) * C(protium) =
(at,no,At mass integer) + constant of equality of energy.

For one gram moleculasr weight of 78 Platinum 195

A B C
Trit. deut Prot
39 39 0
40 37 1
41 35 2
42 33 3
43 31 4
44 29 5
45 27 6
46 25 7
47 23 8
48 21 9
49 19 10
50 17 11
51 15 12
52 13 13
53 11 14
54 9 15
55 7 16
56 5 17
57 3 18
58 1 19

Spot check arithmetic
A B C = 52,13, 13
at no check at mass integer check

52 x 1 = 52 52 x 3 = 156
13 x 1 = 13 13 x 2= 26
13 x 1 = 13 13 x 1 13
-------------- ----------------------------
at no 78 at mass integer 195

QUOD ERAT DEMONSTRANDUM

NOw for the Stoichiometry, the operastor hass less than 1 nanosecond to weight 52 tritium and get them fused nuclearly with nhe two other ingredients..suns temperature = very high pressure

likely required.
if youcant standtheheat,stay out of the kitchen.

So whats missing? I am looking for the coolest way to spend some bux that i inherited lately. Tempted on travelling to europe and try together ?

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